How many kJ of heat energy are released when 2.1 kg of propane are burned?
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By the way, the reaction for the combustion of propane is C3H8(l) + 5O2(g) ? 3CO2(g) + 4H2O(g).
And, for that equation ?H = -2220 kJ/mol.
I greatly appreciate any help!
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Tagged with: c3h8 • combustion • kj • Propane
Filed under: Energy
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This is done, using the enthalpy change for the burning of 1 mol of propane with 5 mol of Oxygen and that the limiting reagent is propane
1)Convert the amt of propane to grams: 2100g
2)Calculate the no. of mol of propane: 2100/ (12×3+8×1)= 47.727 mol
3) Total enthalpy change: 47.727 x -2220 kJ= -105954.545 kJ
Jus to take note, this is an exothermic reaction, therefore the enthalpy change value is negative
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